How to Find x + y from Given Equations?

Finding the sum of $x$ and $y$ from given equations usually involves solving a system of linear equations. Let’s walk through this process step by step.

Step-by-Step Process

  1. Write Down the Equations
    Suppose we have two linear equations:

    1. $a_1x + b_1y = c_1$
    2. $a_2x + b_2y = c_2$

  1. Solve One of the Equations for One Variable
    Choose one of the equations and solve for either $x$ or $y$. For instance, solve the first equation for $x$:

    $x = frac{c_1 – b_1y}{a_1}$

  1. Substitute the Expression into the Other Equation
    Substitute the expression for $x$ into the second equation:

    $a_2frac{c_1 – b_1y}{a_1} + b_2y = c_2$

  1. Solve for y
    Simplify and solve for $y$:

    $frac{a_2c_1 – a_2b_1y}{a_1} + b_2y = c_2$

    Multiply through by $a_1$ to clear the fraction:

    $a_2c_1 – a_2b_1y + a_1b_2y = a_1c_2$

    Combine like terms:

    $a_2c_1 + (a_1b_2 – a_2b_1)y = a_1c_2$

    Solve for $y$:

    $y = frac{a_1c_2 – a_2c_1}{a_1b_2 – a_2b_1}$

  1. Substitute Back to Find x
    Now substitute this value of $y$ back into the expression for $x$:

    $x = frac{c_1 – b_1frac{a_1c_2 – a_2c_1}{a_1b_2 – a_2b_1}}{a_1}$

    Simplify to find $x$

  1. Add x and y
    Finally, add the values of $x$ and $y$ to find $x + y$:

    $x + y = frac{c_1 – b_1frac{a_1c_2 – a_2c_1}{a_1b_2 – a_2b_1}}{a_1} + frac{a_1c_2 – a_2c_1}{a_1b_2 – a_2b_1}$

Example

Let’s use an example to make this clearer. Suppose we have the equations:

  1. $2x + 3y = 6$
  2. $4x – y = 5$

  1. Write Down the Equations
    We already have them:

    1. $2x + 3y = 6$
    2. $4x – y = 5$

  1. Solve One of the Equations for One Variable
    Solve the first equation for $x$:

    $x = frac{6 – 3y}{2}$

  1. Substitute the Expression into the Other Equation
    Substitute into the second equation:

    $4frac{6 – 3y}{2} – y = 5$

    Simplify:

    $2(6 – 3y) – y = 5$

    $12 – 6y – y = 5$

    $12 – 7y = 5$

  1. Solve for y

    $-7y = -7$

    $y = 1$

  1. Substitute Back to Find x
    Substitute $y = 1$ back into the expression for $x$:

    $x = frac{6 – 3(1)}{2}$

    $x = frac{6 – 3}{2}$

    $x = frac{3}{2}$

  1. Add x and y

    $x + y = frac{3}{2} + 1$

    $x + y = frac{3}{2} + frac{2}{2}$

    $x + y = frac{5}{2}$

    So, $x + y = frac{5}{2}$

Conclusion

By following these steps, you can find the sum of $x$ and $y$ from a system of linear equations. Practice with different sets of equations to become more comfortable with this process.

Citations

  1. 1. Khan Academy – Systems of Linear Equations
  2. 2. Purplemath – Solving Systems of Linear Equations
  3. 3. Math is Fun – Solving Simultaneous Equations

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ