Steps to Multiply Complex Numbers

Multiplying complex numbers might seem tricky at first, but it’s straightforward once you understand the process. Complex numbers have the form $a + bi$, where $a$ and $b$ are real numbers, and $i$ is the imaginary unit with the property $i^2 = -1$. Let’s break down the steps to multiply two complex numbers.

Step-by-Step Process

  1. Write Down the Numbers
    Suppose you want to multiply two complex numbers: $(a + bi)$ and $(c + di)$. For example, let’s take $(3 + 2i)$ and $(1 + 4i)$

  1. Use the Distributive Property
    Next, we’ll distribute each term in the first complex number by each term in the second complex number, similar to how you would use the distributive property in algebra:

    $(a + bi)(c + di) = a times c + a times di + bi times c + bi times di$

    Using our example:

    $(3 + 2i)(1 + 4i) = 3 times 1 + 3 times 4i + 2i times 1 + 2i times 4i$

  1. Perform the Multiplications
    Now, multiply each pair of terms:

    $3 times 1 = 3$

    $3 times 4i = 12i$

    $2i times 1 = 2i$

    $2i times 4i = 8i^2$

  1. Combine Like Terms
    Combine the like terms (real parts with real parts, imaginary parts with imaginary parts):

    $3 + 12i + 2i + 8i^2$

  1. Simplify Using $i^2 = -1$
    Recall that $i^2 = -1$. So, replace $i^2$ with $-1$ in the expression:

    $8i^2 = 8 times -1 = -8$

    Now, substitute back into the expression:

    $3 + 12i + 2i – 8$

  1. Final Simplification
    Combine the real parts and the imaginary parts:

    $(3 – 8) + (12i + 2i) = -5 + 14i$

    So, $(3 + 2i)(1 + 4i) = -5 + 14i$

Example Problem

Let’s try another example: $(2 + 3i)(4 – i)$

  1. Distribute the terms:

$(2 + 3i)(4 – i) = 2 times 4 + 2 times -i + 3i times 4 + 3i times -i$

  1. Perform the multiplications:

$2 times 4 = 8$

$2 times -i = -2i$

$3i times 4 = 12i$

$3i times -i = -3i^2$

  1. Combine like terms:

$8 – 2i + 12i – 3i^2$

  1. Simplify using $i^2 = -1$:

$-3i^2 = -3 times -1 = 3$

  1. Substitute back in:

$8 – 2i + 12i + 3$

  1. Final simplification:

$(8 + 3) + (-2i + 12i) = 11 + 10i$

Thus, $(2 + 3i)(4 – i) = 11 + 10i$

Conclusion

Multiplying complex numbers involves using the distributive property, combining like terms, and simplifying using $i^2 = -1$. With practice, this process becomes second nature, allowing you to handle complex numbers with ease.

Citations

  1. 1. Khan Academy – Multiplying complex numbers
  2. 2. Math is Fun – Complex Numbers
  3. 3. Purplemath – Multiplying Complex Numbers

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ