How to Compare Fractions and Mixed Numbers?

Comparing fractions and mixed numbers might seem challenging at first, but with some straightforward steps, you can easily determine which one is larger or smaller.

Step-by-Step Guide

1. Understanding Fractions and Mixed Numbers

  • Fractions represent parts of a whole and are written as $frac{a}{b}$ where ‘a’ is the numerator (number of parts) and ‘b’ is the denominator (total parts).
  • Mixed Numbers combine a whole number and a fraction, such as $3frac{1}{2}$

2. Converting Mixed Numbers to Improper Fractions

To compare mixed numbers with fractions or other mixed numbers, convert them to improper fractions first:

  • Multiply the whole number by the denominator.
  • Add the numerator to this product.
  • Place this sum over the original denominator.

For example, to convert $2frac{3}{4}$:
$2 times 4 + 3 = 8 + 3 = 11$
So, $2frac{3}{4} = frac{11}{4}$

3. Finding a Common Denominator

To compare fractions, they must have the same denominator. This is called finding a common denominator:

  • Determine the least common multiple (LCM) of the denominators.
  • Convert each fraction to an equivalent fraction with this common denominator.

For instance, to compare $frac{2}{3}$ and $frac{3}{4}$:

  • The LCM of 3 and 4 is 12.
  • Convert $frac{2}{3}$ to $frac{8}{12}$ and $frac{3}{4}$ to $frac{9}{12}$

4. Comparing the Numerators

Once the fractions have the same denominator, compare the numerators:

  • The fraction with the larger numerator is the larger fraction.

Using our example, $frac{8}{12} < frac{9}{12}$, so $frac{2}{3} < frac{3}{4}$

5. Comparing Mixed Numbers

If dealing with mixed numbers, compare the whole numbers first:

  • If the whole numbers are different, the mixed number with the larger whole number is greater.
  • If the whole numbers are the same, convert the fractional parts to a common denominator and compare as above.

For example, to compare $3frac{1}{2}$ and $3frac{2}{3}$:

  • Whole numbers are the same (3).
  • Convert $frac{1}{2}$ to $frac{3}{6}$ and $frac{2}{3}$ to $frac{4}{6}$
  • Compare: $frac{3}{6} < frac{4}{6}$, so $3frac{1}{2} < 3frac{2}{3}$

Practical Example

Let’s compare $1frac{1}{4}$ and $frac{5}{3}$:

  • Convert $1frac{1}{4}$ to $frac{5}{4}$
  • Find a common denominator for $frac{5}{4}$ and $frac{5}{3}$. The LCM of 4 and 3 is 12.
  • Convert: $frac{5}{4} = frac{15}{12}$ and $frac{5}{3} = frac{20}{12}$
  • Compare: $frac{15}{12} < frac{20}{12}$, so $1frac{1}{4} < frac{5}{3}$

Conclusion

By converting mixed numbers to improper fractions, finding a common denominator, and comparing numerators, you can easily compare fractions and mixed numbers. Practice these steps to become confident in your comparisons!

Citations

  1. 1. Khan Academy – Comparing Fractions
  2. 2. Math is Fun – Comparing Fractions
  3. 3. Purplemath – Comparing Fractions and Mixed Numbers

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ