What are the steps to subtract polynomials?

Subtracting polynomials may sound complicated, but it’s quite manageable if you follow a systematic approach. Let’s break it down step by step.

  1. Arrange the Polynomials
    First, write down the polynomials you want to subtract in a standard form, which means arranging the terms in descending order of their degrees. For example, if you have two polynomials $P(x) = 3x^3 + 2x^2 – x + 5$ and $Q(x) = x^3 – 4x^2 + 2x – 3$, arrange them as shown.

  1. Distribute the Negative Sign
    When subtracting polynomials, you need to distribute the negative sign across each term of the polynomial being subtracted. This means changing the sign of every term in the second polynomial. For example:

    $(3x^3 + 2x^2 – x + 5) – (x^3 – 4x^2 + 2x – 3)$

    becomes:

    $3x^3 + 2x^2 – x + 5 – x^3 + 4x^2 – 2x + 3$

  1. Combine Like Terms
    Next, combine like terms. Like terms are terms that have the same variable raised to the same power. So, group the $x^3$ terms, $x^2$ terms, $x$ terms, and constant terms together:

    $3x^3 – x^3 + 2x^2 + 4x^2 – x – 2x + 5 + 3$

  1. Simplify Each Group
    Now, simplify each group by performing the arithmetic operations. For our example:

    • Combine the $x^3$ terms: $3x^3 – x^3 = 2x^3$
    • Combine the $x^2$ terms: $2x^2 + 4x^2 = 6x^2$
    • Combine the $x$ terms: $-x – 2x = -3x$
    • Combine the constant terms: $5 + 3 = 8$

  1. Write the Result
    Finally, write down the simplified polynomial:

    $2x^3 + 6x^2 – 3x + 8$

Example Problem

Let’s go through another example to solidify the steps. Suppose we want to subtract $R(x) = 5x^2 – 3x + 7$ from $S(x) = 2x^2 + x – 4$

  1. Arrange the polynomials:

$S(x) = 2x^2 + x – 4$

$R(x) = 5x^2 – 3x + 7$

  1. Distribute the negative sign:

$2x^2 + x – 4 – (5x^2 – 3x + 7)$

$= 2x^2 + x – 4 – 5x^2 + 3x – 7$

  1. Combine like terms:

$2x^2 – 5x^2 + x + 3x – 4 – 7$

  1. Simplify each group:
  • Combine the $x^2$ terms: $2x^2 – 5x^2 = -3x^2$
  • Combine the $x$ terms: $x + 3x = 4x$
  • Combine the constant terms: $-4 – 7 = -11$
  1. Write the result:

$-3x^2 + 4x – 11$

Conclusion

By following these steps—arranging the polynomials, distributing the negative sign, combining like terms, and simplifying—you can easily subtract any polynomials. Practice a few problems on your own to get the hang of it. Happy calculating!

Citations

  1. 1. Khan Academy – Adding and Subtracting Polynomials
  2. 2. Purplemath – Adding and Subtracting Polynomials
  3. 3. Math is Fun – Polynomials

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ