How to Subtract Mixed Numbers?

Subtracting mixed numbers might seem tricky at first, but with a few steps, it becomes straightforward. Let’s break it down.

Step-by-Step Guide

  1. Convert Mixed Numbers to Improper Fractions
    Mixed numbers consist of a whole number and a fraction. To subtract them, first convert each mixed number to an improper fraction. An improper fraction has a numerator larger than its denominator. For example, to convert
    $2frac{3}{4}$:

    1. Multiply the whole number by the denominator: $2 times 4 = 8$
    2. Add the numerator to the result: $8 + 3 = 11$
    3. Place the result over the original denominator: $frac{11}{4}$

  1. Find a Common Denominator
    To subtract fractions, they must have the same denominator. If the fractions already share a denominator, you can skip this step. Otherwise, find the least common denominator (LCD). For instance, if subtracting $frac{11}{4}$ and $frac{5}{6}$, the LCD of 4 and 6 is 12.

  1. Convert Fractions to Equivalent Fractions
    Convert each fraction to an equivalent fraction with the LCD as the new denominator:

    • For $frac{11}{4}$: $frac{11 times 3}{4 times 3} = frac{33}{12}$
    • For $frac{5}{6}$: $frac{5 times 2}{6 times 2} = frac{10}{12}$

  1. Subtract the Numerators
    Now that the fractions have the same denominator, subtract the numerators:
    $frac{33}{12} – frac{10}{12} = frac{23}{12}$

  1. Simplify the Result
    If the resulting fraction is improper, convert it back to a mixed number:

    • Divide the numerator by the denominator: $23 div 12 = 1$ remainder $11$
    • The quotient is the whole number, and the remainder is the new numerator: $1frac{11}{12}$

Example Problem

Let’s subtract $3frac{2}{5}$ from $5frac{3}{10}$:

  1. Convert to improper fractions:
    • $5frac{3}{10} = frac{53}{10}$
    • $3frac{2}{5} = frac{17}{5} = frac{34}{10}$
  2. Find the common denominator (which is 10 here).
  3. Convert to equivalent fractions:
    • $frac{53}{10}$ (already has the common denominator)
    • $frac{34}{10}$ (already has the common denominator)
  4. Subtract the numerators:
    • $frac{53}{10} – frac{34}{10} = frac{19}{10}$
  5. Simplify the result:
    • $frac{19}{10} = 1frac{9}{10}$

Conclusion

Subtracting mixed numbers involves converting them to improper fractions, finding a common denominator, subtracting, and simplifying the result. With practice, these steps become second nature, making the process much easier.

Citations

  1. 1. Khan Academy – Subtracting Mixed Numbers
  2. 2. Math is Fun – Mixed Numbers
  3. 3. Purplemath – Mixed Numbers

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ