What is the vertex form of a parabola?

Understanding the vertex form of a parabola is crucial for graphing and analyzing quadratic functions. The vertex form of a parabola’s equation is given by:

$y = a(x – h)^2 + k$

Here, $(h, k)$ represents the vertex of the parabola, and the parameter $a$ affects the width and direction of the parabola.

Breaking Down the Vertex Form

Vertex $(h, k)$

The point $(h, k)$ is the vertex of the parabola, which is the highest or lowest point on the graph, depending on the value of $a$. If $a$ is positive, the parabola opens upwards, making the vertex the lowest point. Conversely, if $a$ is negative, the parabola opens downwards, making the vertex the highest point.

Parameter $a$

The parameter $a$ affects the width and direction of the parabola. If $|a| > 1$, the parabola becomes narrower, while if $|a| < 1$, it becomes wider. Additionally, the sign of $a$ determines the direction the parabola opens:

  • $a > 0$: Opens upwards
  • $a < 0$: Opens downwards

Example

Let’s consider an example to illustrate the vertex form. Suppose we have the equation:

$y = 2(x – 3)^2 + 4$

In this equation, $a = 2$, $h = 3$, and $k = 4$. Therefore, the vertex of the parabola is $(3, 4)$. Since $a = 2$ (a positive value greater than 1), the parabola opens upwards and is narrower than the standard parabola $y = x^2$

Converting from Standard Form to Vertex Form

Sometimes, you may need to convert a quadratic equation from its standard form $y = ax^2 + bx + c$ to the vertex form. This can be done by completing the square.

Steps to Complete the Square

  1. Start with the standard form: $y = ax^2 + bx + c$
  2. Factor out $a$ from the $x^2$ and $x$ terms: $y = a(x^2 + frac{b}{a}x) + c$
  3. Add and subtract $frac{b^2}{4a^2}$ inside the parenthesis: $y = abig(x^2 + frac{b}{a}x + frac{b^2}{4a^2} – frac{b^2}{4a^2}big) + c$
  4. Rewrite the perfect square trinomial: $y = abig((x + frac{b}{2a})^2 – frac{b^2}{4a^2}big) + c$
  5. Simplify: $y = a(x + frac{b}{2a})^2 – frac{b^2}{4a} + c$
  6. Combine constants: $y = a(x + frac{b}{2a})^2 + (c – frac{b^2}{4a})$

Now, the equation is in vertex form $y = a(x – h)^2 + k$, where $h = -frac{b}{2a}$ and $k = c – frac{b^2}{4a}$

Conclusion

The vertex form of a parabola provides a clear and concise way to identify the vertex and understand the parabola’s shape and direction. By mastering this form, you can easily graph quadratic functions and analyze their key features.

Citations

  1. 1. Khan Academy – Vertex Form
  2. 2. Purplemath – Vertex Form
  3. 3. Math is Fun – Parabola

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ