What is the Binomial Theorem?

The binomial theorem is a fundamental principle in algebra that provides a quick way to expand expressions that are raised to a power. It is particularly useful when dealing with polynomials and can save a lot of time compared to multiplying the expression out manually.

The Binomial Theorem Formula

The binomial theorem states that for any positive integer $n$, the expansion of $(a + b)^n$ can be expressed as:

$(a + b)^n = sum_{k=0}^{n} binom{n}{k} a^{n-k} b^k$

Here, $binom{n}{k}$ is the binomial coefficient, which is calculated using the combination formula:

$binom{n}{k} = frac{n!}{k!(n-k)!}$

Understanding Binomial Coefficients

Binomial coefficients, $binom{n}{k}$, represent the coefficients in the expanded form of $(a + b)^n$. These coefficients can also be found in Pascal’s Triangle, where each number is the sum of the two numbers directly above it.

For example, the expansion of $(a + b)^3$ is:

$(a + b)^3 = binom{3}{0}a^3b^0 + binom{3}{1}a^2b^1 + binom{3}{2}a^1b^2 + binom{3}{3}a^0b^3$

Simplifying this, we get:

$(a + b)^3 = 1a^3 + 3a^2b + 3ab^2 + 1b^3$

Example: Expanding $(x + 2)^4$

Let’s use the binomial theorem to expand $(x + 2)^4$

  1. Identify $a = x$, $b = 2$, and $n = 4$
  2. Apply the binomial theorem formula:

$(x + 2)^4 = sum_{k=0}^{4} binom{4}{k} x^{4-k} 2^k$

  1. Calculate each term:
    • For $k=0$: $binom{4}{0} x^4 2^0 = 1 cdot x^4 cdot 1 = x^4$
    • For $k=1$: $binom{4}{1} x^3 2^1 = 4 cdot x^3 cdot 2 = 8x^3$
    • For $k=2$: $binom{4}{2} x^2 2^2 = 6 cdot x^2 cdot 4 = 24x^2$
    • For $k=3$: $binom{4}{3} x^1 2^3 = 4 cdot x cdot 8 = 32x$
    • For $k=4$: $binom{4}{4} x^0 2^4 = 1 cdot 1 cdot 16 = 16$

Combining these terms, we get:

$(x + 2)^4 = x^4 + 8x^3 + 24x^2 + 32x + 16$

Conclusion

Understanding the binomial theorem allows you to expand expressions quickly and efficiently. By mastering the use of binomial coefficients and the general formula, you can tackle a wide range of polynomial expansions with ease.

Citations

  1. 1. Khan Academy – Binomial Theorem
  2. 2. Wolfram MathWorld – Binomial Theorem
  3. 3. Paul’s Online Math Notes – Binomial Theorem

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ