The Formula for the Sum of an Infinite Geometric Progression

An infinite geometric progression is a sequence of numbers where each term is found by multiplying the previous term by a constant factor called the common ratio. We can represent this sequence as:

$a, ar, ar^2, ar^3, …$

where:

  • $a$ is the first term
  • $r$ is the common ratio

The sum of an infinite geometric progression is the sum of all the terms in the sequence. However, not all infinite geometric progressions have a finite sum. The sum only exists if the absolute value of the common ratio is less than 1 (i.e., $|r| < 1$).

Understanding the Formula

The formula for the sum of an infinite geometric progression is:

$S = frac{a}{1 – r}$

where:

  • $S$ is the sum of the infinite geometric progression
  • $a$ is the first term
  • $r$ is the common ratio

This formula can be derived by considering the following:

  1. The sum of the first $n$ terms of a geometric progression:

$S_n = frac{a(1 – r^n)}{1 – r}$

  1. As $n$ approaches infinity, the value of $r^n$ approaches zero:

This is true because if $|r| < 1$, then $r^n$ gets smaller and smaller as $n$ increases. For example, if $r = 0.5$, then $r^n$ becomes 0.5, 0.25, 0.125, and so on as $n$ increases. This means that as $n$ approaches infinity, $r^n$ approaches zero.

  1. Taking the limit as $n$ approaches infinity:

When we take the limit as $n$ approaches infinity in the formula for $S_n$, the term $r^n$ becomes zero, leaving us with:

$S = frac{a}{1 – r}$

Examples

Let’s illustrate this with some examples:

Example 1:

Find the sum of the infinite geometric progression: $1, frac{1}{2}, frac{1}{4}, frac{1}{8}, …$

Here, the first term $a = 1$ and the common ratio $r = frac{1}{2}$. Since $|r| < 1$, the sum exists. Using the formula, we get:

$S = frac{1}{1 – frac{1}{2}} = frac{1}{frac{1}{2}} = 2$

Therefore, the sum of the infinite geometric progression is 2.

Example 2:

Find the sum of the infinite geometric progression: $3, -1, frac{1}{3}, -frac{1}{9}, …$

Here, the first term $a = 3$ and the common ratio $r = -frac{1}{3}$. Since $|r| < 1$, the sum exists. Using the formula, we get:

$S = frac{3}{1 – (-frac{1}{3})} = frac{3}{frac{4}{3}} = frac{9}{4}$

Therefore, the sum of the infinite geometric progression is $frac{9}{4}$

Applications of the Formula

The formula for the sum of an infinite geometric progression has various applications in mathematics, physics, and other fields. Here are some examples:

  • Calculating the value of repeating decimals: Repeating decimals can be expressed as infinite geometric progressions. For example, the repeating decimal 0.333… can be written as the infinite geometric progression: $0.3 + 0.03 + 0.003 + …$. The first term $a = 0.3$ and the common ratio $r = 0.1$. Applying the formula, we get:

$S = frac{0.3}{1 – 0.1} = frac{0.3}{0.9} = frac{1}{3}$

  • Modeling exponential decay: Exponential decay processes, such as radioactive decay or the cooling of a hot object, can be modeled using infinite geometric progressions. The formula can be used to calculate the total amount of decay over an infinite period.

  • Calculating the area of certain geometric figures: The formula can be used to calculate the area of certain geometric figures, such as the area of a circle or the area of a sphere.

Conclusion

The formula for the sum of an infinite geometric progression is a powerful tool that can be used to solve a variety of problems in mathematics, physics, and other fields. Understanding the formula and its derivation is essential for anyone working with infinite geometric progressions.

3. Brilliant – Infinite Geometric Series

Citations

  1. 1. Khan Academy – Infinite Geometric Series
  2. 2. Math is Fun – Geometric Series

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ