How to Calculate the Sum of a Series?

Calculating the sum of a series can seem daunting, but it’s a fundamental concept in mathematics. A series is simply the sum of the terms of a sequence. Let’s break down the process for different types of series.

Arithmetic Series

An arithmetic series is one where each term is obtained by adding a constant difference to the previous term. For example, 2, 5, 8, 11 is an arithmetic series with a common difference of 3.

Formula

The sum of the first $n$ terms of an arithmetic series can be calculated using the formula:

$S_n = frac{n}{2} (a + l)$

where $S_n$ is the sum of the first $n$ terms, $a$ is the first term, and $l$ is the last term.

Example

Consider the series 2, 5, 8, 11. To find the sum of the first 4 terms:

  • First term ($a$) = 2
  • Last term ($l$) = 11
  • Number of terms ($n$) = 4

Using the formula:

$S_4 = frac{4}{2} (2 + 11) = 2 times 13 = 26$

So, the sum of the first 4 terms is 26.

Geometric Series

A geometric series is one where each term is obtained by multiplying the previous term by a constant ratio. For example, 3, 6, 12, 24 is a geometric series with a common ratio of 2.

Formula

The sum of the first $n$ terms of a geometric series can be calculated using the formula:

$S_n = a frac{1 – r^n}{1 – r}$

where $S_n$ is the sum of the first $n$ terms, $a$ is the first term, and $r$ is the common ratio.

Example

Consider the series 3, 6, 12, 24. To find the sum of the first 4 terms:

  • First term ($a$) = 3
  • Common ratio ($r$) = 2
  • Number of terms ($n$) = 4

Using the formula:

$S_4 = 3 frac{1 – 2^4}{1 – 2} = 3 frac{1 – 16}{-1} = 3 times 15 = 45$

So, the sum of the first 4 terms is 45.

Infinite Series

Some series go on forever, and we call these infinite series. Not all infinite series have a sum, but some do. A common example is the geometric series where the absolute value of the common ratio is less than 1.

Formula

The sum of an infinite geometric series can be calculated using the formula:

$S = frac{a}{1 – r}$

where $S$ is the sum, $a$ is the first term, and $r$ is the common ratio.

Example

Consider the series 1, 0.5, 0.25, 0.125, …, where the common ratio is 0.5.

  • First term ($a$) = 1
  • Common ratio ($r$) = 0.5

Using the formula:

$S = frac{1}{1 – 0.5} = frac{1}{0.5} = 2$

So, the sum of this infinite series is 2.

Conclusion

Understanding how to calculate the sum of different types of series is essential in various fields of mathematics and science. Whether it’s an arithmetic series, a geometric series, or even an infinite series, knowing the right formula can simplify the process significantly.

Citations

  1. 1. Khan Academy – Arithmetic Series
  2. 2. Khan Academy – Geometric Series
  3. 3. Paul’s Online Math Notes – Series
  4. 4. Wolfram MathWorld – Series

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ