How to Express a Fraction with a Negative Exponent?

When you come across a fraction with a negative exponent, it can look a bit intimidating at first. But don’t worry—it’s actually quite simple once you understand the basic rules.

Understanding Negative Exponents

A negative exponent indicates that you need to take the reciprocal of the base. The reciprocal of a number is simply 1 divided by that number. For example, the reciprocal of 2 is $frac{1}{2}$, and the reciprocal of $frac{3}{4}$ is $frac{4}{3}$

General Rule

The general rule for any base $a$ raised to a negative exponent $-n$ is:

$a^{-n} = frac{1}{a^n}$

This means that you flip the base to its reciprocal and change the exponent to positive.

Applying the Rule to Fractions

When you have a fraction raised to a negative exponent, you apply the same rule. Let’s break it down with an example.

Example: $left(frac{2}{3}right)^{-2}$

  1. Reciprocal: First, take the reciprocal of the fraction $frac{2}{3}$, which is $frac{3}{2}$
  2. Positive Exponent: Change the negative exponent to a positive exponent.

So,

$left(frac{2}{3}right)^{-2} = left(frac{3}{2}right)^2$

  1. Solve: Now, raise the reciprocal to the positive exponent.

$left(frac{3}{2}right)^2 = frac{3^2}{2^2} = frac{9}{4}$

Therefore, $left(frac{2}{3}right)^{-2} = frac{9}{4}$

Another Example: $left(frac{5}{7}right)^{-3}$

  1. Reciprocal: Take the reciprocal of $frac{5}{7}$, which is $frac{7}{5}$
  2. Positive Exponent: Change the exponent to positive.

So,

$left(frac{5}{7}right)^{-3} = left(frac{7}{5}right)^3$

  1. Solve: Raise the reciprocal to the positive exponent.

$left(frac{7}{5}right)^3 = frac{7^3}{5^3} = frac{343}{125}$

Therefore, $left(frac{5}{7}right)^{-3} = frac{343}{125}$

Why Does This Work?

The concept of negative exponents is rooted in the properties of exponents and the rules of arithmetic. Essentially, a negative exponent tells you to perform the inverse operation of multiplication, which is division. By taking the reciprocal and changing the exponent to positive, you are effectively performing this inverse operation.

Practical Applications

Understanding how to work with negative exponents is crucial in various fields such as physics, engineering, and computer science. For instance, in physics, you might encounter formulas where you need to manipulate exponents to solve for a particular variable.

Conclusion

In summary, expressing a fraction with a negative exponent involves taking the reciprocal of the fraction and changing the exponent to positive. This simple rule can help you navigate through more complex mathematical problems with ease.

Citations

  1. 1. Khan Academy – Negative Exponents
  2. 2. Math is Fun – Exponent Laws
  3. 3. Purplemath – Negative Exponents

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ