What does

The expression $16x^2 + 48x + 36$ is a quadratic polynomial. Quadratic polynomials are algebraic expressions of the form $ax^2 + bx + c$, where $a$, $b$, and $c$ are constants. In our specific case, $a = 16$, $b = 48$, and $c = 36$

Factoring the Polynomial

One way to understand this quadratic polynomial is to factor it. Factoring involves rewriting the polynomial as a product of simpler expressions. Let’s factor $16x^2 + 48x + 36$ step-by-step:

  1. Identify the Greatest Common Factor (GCF): In this case, the GCF of $16x^2$, $48x$, and $36$ is 4. However, we will see that the polynomial can be factored further.

  2. Rewrite the Polynomial: Notice that $16x^2$, $48x$, and $36$ are perfect squares or products of perfect squares. This suggests that the polynomial might be a square of a binomial. Let’s test this hypothesis.

  3. Find the Binomial: We look for a binomial $(ax + b)$ such that $(ax + b)^2 = 16x^2 + 48x + 36$

  4. Solve for $a$ and $b$:

  • The first term $16x^2$ suggests that $a = 4$ because $(4x)^2 = 16x^2$
  • The constant term $36$ suggests that $b = 6$ because $6^2 = 36$
  • Verify the middle term $48x$: $2ab = 2(4x)(6) = 48x$

So, the binomial is $(4x + 6)$, and the quadratic polynomial can be factored as:

$(16x^2 + 48x + 36) = (4x + 6)^2$

Graphical Interpretation

When you graph the quadratic polynomial $16x^2 + 48x + 36$, it forms a parabola. Since the quadratic is a perfect square, the vertex of the parabola touches the x-axis at a single point. The vertex form of a quadratic equation is given by $a(x – h)^2 + k$, where $(h, k)$ is the vertex of the parabola.

For $16x^2 + 48x + 36$, rewriting it in vertex form gives us:

$(4x + 6)^2 = 16(x + frac{3}{2})^2$

Thus, the vertex of the parabola is at $(-frac{3}{2}, 0)$. This means the graph of the polynomial touches the x-axis at $x = -frac{3}{2}$ and opens upwards because the coefficient of $x^2$ (16) is positive.

Conclusion

In summary, the expression $16x^2 + 48x + 36$ is a quadratic polynomial that can be factored into $(4x + 6)^2$. This means it represents a parabola with a vertex at $(-frac{3}{2}, 0)$, which opens upwards. Understanding how to factor and graph such polynomials is fundamental in algebra and helps in solving quadratic equations and analyzing their properties.

Citations

  1. 1. Khan Academy – Factoring quadratics
  2. 2. Purplemath – Factoring Quadratics
  3. 3. Math is Fun – Quadratic Equations

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ