What is the process for solving complex fractions?

Complex fractions can seem daunting at first, but with a systematic approach, they become much more manageable. Let’s break down the process step-by-step.

  1. Simplify the Numerator and Denominator
    First, simplify both the numerator and the denominator of the complex fraction separately. This means you might need to combine fractions within the numerator and denominator.

    For example, let’s consider the complex fraction:

    $frac{frac{1}{2} + frac{1}{3}}{frac{1}{4} – frac{1}{6}}$

Simplify the Numerator

Combine the fractions in the numerator:

$frac{1}{2} + frac{1}{3} = frac{3}{6} + frac{2}{6} = frac{5}{6}$

Simplify the Denominator

Combine the fractions in the denominator:

$frac{1}{4} – frac{1}{6} = frac{3}{12} – frac{2}{12} = frac{1}{12}$

So now, the complex fraction looks like this:

$frac{frac{5}{6}}{frac{1}{12}}$

  1. Multiply by the Reciprocal
    To simplify the complex fraction, multiply the numerator by the reciprocal of the denominator.

    The reciprocal of $frac{1}{12}$ is $12$. So, multiply $frac{5}{6}$ by $12$:

    $frac{5}{6} times 12 = frac{5 times 12}{6} = frac{60}{6} = 10$

    Thus, the simplified form of the complex fraction is $10$

  1. Simplify Further if Necessary
    Sometimes, after multiplying by the reciprocal, you might need to simplify the result further. In our example, $10$ is already in its simplest form.

Another Example

Let’s look at another example to reinforce the process:

$frac{frac{2}{3} – frac{1}{5}}{frac{4}{7} + frac{1}{2}}$

Simplify the Numerator

Combine the fractions in the numerator:

$frac{2}{3} – frac{1}{5} = frac{10}{15} – frac{3}{15} = frac{7}{15}$

Simplify the Denominator

Combine the fractions in the denominator:

$frac{4}{7} + frac{1}{2} = frac{8}{14} + frac{7}{14} = frac{15}{14}$

So now, the complex fraction looks like this:

$frac{frac{7}{15}}{frac{15}{14}}$

Multiply by the Reciprocal

Multiply the numerator by the reciprocal of the denominator:

$frac{7}{15} times frac{14}{15} = frac{7 times 14}{15 times 15} = frac{98}{225}$

The simplified form of the complex fraction is $frac{98}{225}$. If this can be simplified further, do so; in this case, it is already in simplest form.

Conclusion

Understanding the process of solving complex fractions involves simplifying the numerator and denominator, then multiplying by the reciprocal of the denominator. With practice, this process becomes intuitive and straightforward. Happy calculating!

Citations

  1. 1. Khan Academy – Complex Fractions
  2. 2. Math is Fun – Simplifying Complex Fractions
  3. 3. Purplemath – Complex Fractions

Related

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H + HO2 → O2 + H2 k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O2 k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) H + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-5 s^-1) φ

Table 1 Reactions, rate constants and activation energies used in the model* No. Reaction kopt (M⁻¹ s⁻¹) 1 OH + H₂ → H + H₂O 3.74 x 10⁷ 2 OH + HO₂ → HO₂ + OH⁻ 5 x 10⁹ 3 OH + H₂O₂ → HO₂ + H₂O 3.8 x 10⁷ 4 OH + O₂ → O₂ + OH 9.96 x 10⁹ 5 OH + HO₂ → O₂ + H₂O 7.1 x 10⁹ 6 OH + OH → H₂O₂ 5.3 x 10⁹ 7 OH + e⁻aq → OH⁻ 3 x 10¹⁰ 8 H + O₂ → HO₂ 2.0 x 10¹⁰ 9 H + HO₂ → H₂O₂ 2.0 x 10¹⁰ 10 H + H₂O₂ → OH + H₂O 3.44 x 10⁷ 11 H + OH → H₂O 1.4 x 10¹⁰ 12 H + H → H₂ 1.94 x 10¹⁰ 13 e⁻aq + O₂ → O₂⁻ 1.9 x 10¹⁰ 14 e⁻aq + O₂ → HO₂⁻ + OH⁻ 1.3 x 10¹⁰ 15 e⁻aq + HO₂ 2.0 x 10¹⁰ 16 e⁻aq + H₂O₂ 1.1 x 10¹⁰ 17 e⁻aq + HO₂ → OH + OH⁻ 1.3 x 10¹⁰ 18 e⁻aq + H⁺ → H 2.3 x 10¹⁰ 19 e⁻aq + e⁻aq → H₂ + OH⁻ + OH⁻ 2.5 x 10⁹ 20 HO₂ + O₂ → O₂ + HO₂ 1.3 x 10⁹ 21 HO₂ + HO₂ → O₂ + H₂O₂ 8.3 x 10⁵ 22 HO₂ + HO₂ → O₂ + OH + H₂O 3.7 23 HO₂ + HO₂ → O₂ + O₂ + OH + H₂O 7 x 10⁵ s⁻¹ 24 H⁺ + O₂⁻ → HO₂ 4.5 x 10¹⁰ 25 H⁺ + O₂⁻ → O₂ 2.0 x 10¹⁰ 26 H⁺ + OH⁻ 1.4 x 10¹¹ 27 H⁺ + HO₂⁻ 2 x 10¹⁰ 28 H₂O₂ → HO₂ + H⁺ + OH⁻ 2.5 x 10⁻⁵ s⁻¹ 29 H₂O₂ → H⁺ + OH⁻ 1.4 x 10⁻⁷ s⁻¹ 30 O₂ + O₂ → O₂ + HO₂ + OH⁻ 0.3 31 O₂ + H₂O₂ → O₂ + OH + OH 16 32

(2) O3 + H → O2 + OH k2 = 1.78×10^-11 cm^3 s^-1 (3) O + OH → O2 + H k3 = 4.40×10^-11 cm^3 s^-1 (5) O + HO2 → O2 + OH k5 = 3.50×10^-11 cm^3 s^-1 (6) H2O + O → 2 OH k6 = 5.40×10^-12 cm^3 s^-1 (9) OH + HO2 → O2 + H2O k9 = 4.00×10^-11 cm^3 s^-1 (10) HO2 + HO2 → O2 + H2O2 k10 = 2.50×10^-12 cm s^-1 (11) O + O2 + M → O3 + M k11 = 1.05×10^-34 cm^6 s^-1 (14) H + O2 + M → HO2 + M k14 = 8.08×10^-32 cm^6 s^-1 (15) OH + H + M → H2O + M k15 = 3.31×10^-27 cm^6 s^-1 (16) O2 + hv → 2 O k16 = (1.26×10^-8 s^-1) φ (17) H2O + hv → H + OH k17 = (3.4×10^-6 s^-1) φ (18) O3 + hv → O2 + O k18 = (7.10×10^-8 s^-1) φ